Re: Help with Unicode decompiling problem

From: Ben Yenko-Martinka (
Date: Thu Nov 04 1999 - 20:58:59 EST

In which case it still doesn't matter because as Markus pointed out, char is
an unsigned type so the high bit isn't treated as a sign thus there is none
to get shifted with either operator except as data so & 0xF isn't necessary
for the high nibble, correct? Or is the type transparent to the shift

Quibbles 'n' Bits ...

Ashley Yakeley wrote:

> Whoops... as Ben Yenko-Martinka pointed out to me, the right-shift
> operator doesn't matter if you're doing &0xF, unless of course you wanted
> to do:
> hexBuffer[2] = hex[c >>> 12];
> --
> Ashley Yakeley, Seattle WA
> Almost empty page: <>

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