Re: What's in a wchar_t string on unix?

From: Frank Yung-Fong Tang (ytang0648@aol.com)
Date: Wed Mar 03 2004 - 14:13:17 EST

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    Clark Cox wrote on 3/3/2004, 1:28 PM:

    > From the C standard:
    >
    > __STDC_ISO_10646_ _An integer constant of the formyyyymmL(for example,
    > 199712L), intended to indicate that values of type wchar_t are the
    > coded representations of the characters defined by ISO/IEC10646, along
    > with all amendments and technical corrigenda as of the specified year
    > and month.
    >
    > This, to me suggests that wchar_t would indeed be a 32-bit type (well,
    > at least a 20-bit type) when this macro is defined. However, to be
    > sure, I'd suggest posting to news:comp.std.c

    The language in the standard does not prevent someone to make it 16
    bits or 64 bits when that macro is defined, right?

    And what does the year and month mean?

    >
    >
    > On Mar 03, 2004, at 12:38, Frank Yung-Fong Tang wrote:
    >
    > > oh. This is the first time I hear about this. Thanks about your
    > > information. Does it also mean wchar_t is 4 bytes if __STDC_ISO_10646__
    > > is defined? or does it only mean wchar_t hold the character in
    > > ISO_10646
    > > (which mean it could be 2 bytes, 4 bytes or more than that?)
    > >
    > > Noah Levitt wrote on 3/2/2004, 1:33 PM:
    > >
    > >> As specified in C99 (and maybe earlier), if the macro
    > >> __STDC_ISO_10646__ is defined, then wchar_t values are ucs4.
    > >> Otherwise, wchar_t is an opaque type and you can't be sure
    > >> what it is.
    > >>
    > >> Noah
    >
    > --
    > Clark S. Cox III
    > clarkcox3@mac.com
    > http://homepage.mac.com/clarkcox3/
    > http://homepage.mac.com/clarkcox3/blog/B1196589870/index.html

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